[英]how I could regex ruby replace by group 10 using gsub?
Im trying to gsub replace a string using a group 10 but instead of this ruby replace by group 1 and 0 I use this in gsub replacement 我试图使用组10 gsub替换字符串,但不是用组1和0将此红宝石替换,而是在gsub替换中使用它
gsub \\10xp
"smnm nmnmn nmnmn dsdsf sffddf sffdfd dfsff fdsdsfd fsdds ssfsff".gsub(/(\S+) (\S+) (\S+) (\S+) (\S+) (\S+) (\S+) (\S+) (\S+) (\S+)/,"\\10xp")
for replace and obtain the group 1 and the string "0xp" 用于替换并获取组1和字符串“ 0xp”
How I could solve this 我该如何解决
Please help me 请帮我
Not sure how to reference a double digit capture group, but you can always just reference a name with something like: 不确定如何引用两位数捕获组,但是您始终可以仅引用具有以下内容的名称:
"smnm nmnmn nmnmn dsdsf sffddf sffdfd dfsff fdsdsfd fsdds ssfsff".
gsub(/(\S+) (\S+) (\S+) (\S+) (\S+) (\S+) (\S+) (\S+) (\S+) (?<ten>\S+)/,
'\k<ten>xp')
# "ssfsffxp"
No one known regex engine does support unnamed groups beyond [0..9]
region. 没有一个已知的正则表达式引擎不支持
[0..9]
区域以外的未命名组。 Use named_captures
instead, or use uncaptured groups (?:...)
, or use wiser regex: 请改用
named_captures
或使用未捕获的组(?:...)
或使用更明智的正则表达式:
"smnm nmnmn nmnmn dsdsf sffddf sffdfd dfsff fdsdsfd fsdds ssfsff".
gsub(/((?:\S+\s+){9})(\S+)/, "\\1 \\2xp")
# ⇑ second group
# ⇑⇑⇑ nine times
# ⇑⇑⇑ don’t capture this!
# ⇑ first group
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.