使用保存键按属性值对对象的Javascript数组进行排序

Question

How to sort array of objects by property 'cost' with holding string keys?

Start array :

aparts: {
    apart1 : {id: "1", status: 2, cost: 10033450},
    apart2 : {id: "2", status: 2, cost: 5214000},
    apart3 : {id: "3", status: 2, cost: 7314300},
    apart4 : {id: "4", status: 1, cost: 9261700}    
}

Want to array:

aparts: {
    apart2 : {id: "2", status: 2, cost: 5214000},
    apart3 : {id: "3", status: 2, cost: 7314300},
    apart4 : {id: "4", status: 1, cost: 9261700},
    apart1 : {id: "1", status: 2, cost: 10033450}   
}

Answer 1

The order of properties is not guaranteed. See, for example here:

https://stackoverflow.com/a/5525820/1250301

If you want something ordered, then you need to use an array. The transformation is pretty straightforward:

 var aparts = { apart1 : {id: "1", status: 2, cost: 10033450}, apart2 : {id: "2", status: 2, cost: 5214000}, apart3 : {id: "3", status: 2, cost: 7314300}, apart4 : {id: "4", status: 1, cost: 9261700} }; var arr = Object.keys(aparts).map(function(k) { return aparts[k]; }).sort(function(a,b) { return a.cost - b.cost }); console.log(arr); 

Answer 2

 const aparts = { apart1: {id:"1", status: 2, cost: 10033450}, apart2: {id:"2", status: 2, cost: 5214000}, apart3: {id:"3", status: 2, cost: 7314300}, apart4: {id:"4", status: 1, cost: 9261700} }; const arr = Object.keys(aparts) .map(k => (aparts[k])) .sort((a,b) => (a.cost - b.cost)) .map(k => ({["apart" + k.id]: k})) ; console.log(arr); 

Answer 3

I believe you are looking for a Map. Which is what your irregular object matches.

 let aparts= { apart1: { id: "1", status: 2, cost: 10033450 }, apart2: { id: "2", status: 2, cost: 5214000 }, apart3: { id: "3", status: 2, cost: 7314300 }, apart4: { id: "4", status: 1, cost: 9261700 } }; let sorted = Object.entries(aparts).map(x => Object.assign(x[1], { apart: x[0] })).sort((a, b) => a.cost - b.cost); let result = new Map(sorted.map(x => ([x.apart, (delete x.apart, x)]))); console.log(...result)