[英]How to convert map to dataframe?
m is a map as following: m是如下地图:
scala> m
res119: scala.collection.mutable.Map[Any,Any] = Map(A-> 0.11164610291904906, B-> 0.11856755943424617, C -> 0.1023171832681312)
I want to get: 我想得到:
name score
A 0.11164610291904906
B 0.11856755943424617
C 0.1023171832681312
How to get the final dataframe? 如何获得最终的数据帧?
First covert it to a Seq
, then you can use the toDF()
function. 首先将其转换为Seq
,然后您可以使用toDF()
函数。
val spark = SparkSession.builder.getOrCreate()
import spark.implicits._
val m = Map("A"-> 0.11164610291904906, "B"-> 0.11856755943424617, "C" -> 0.1023171832681312)
val df = m.toSeq.toDF("name", "score")
df.show
Will give you: 会给你:
+----+-------------------+
|name| score|
+----+-------------------+
| A|0.11164610291904906|
| B|0.11856755943424617|
| C| 0.1023171832681312|
+----+-------------------+
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