计算句子中用空格隔开的所有单词

Question

in Python I want an user to type a sentence using the Input argument.

zin = input("Typ een zinnetje: ")

In a function I want to count all words (everything separated by spaces.) how do I do this?

this is what I have so far.

zin = input("Typ een zinnetje: ")
def gemiddelde():
    aantal = zin.count(zin)
    return aantal

print (gemiddelde())

This prints 1 no matter what.

Answer 1

split will break string by space and len will return length:

zin = input("Typ een zinnetje: ")
def gemiddelde():
    aantal = len(zin.split())
    return aantal

print (gemiddelde())

Answer 2

you need to split sentence by space and then use len

zin = raw_input("Typ een zinnetje: ")
def gemiddelde():
    aantal = len(zin.split(' '))
    return aantal

print (gemiddelde())

Answer 3

zin = input("Typ een zinnetje: ")
def gemiddelde():
        aantal = zin.split(" ")
        return aantal.__len__()

print (gemiddelde())

Answer 4

Further to the answers before me, split will split the string on every occurrence of a space meaning that it may read more words if there are things like double spaces or leading/trailing spaces. It may be worth doing some quick checks to make sure what you get is actually the number of words.

zin = input("Typ een zinnetje: ")

def gemiddelde():
    aantal = zin.split(" ")
    num = sum(len(x) > 0 for x in aantal)
    return num

print (gemiddelde())

Answer 5

In a single line,

def count_words(s):
    return len(s.split())

The split() function will split the string s into list of words , where the delimiter for the split is whitespace . The len() will return the number of elements that were obtained when the string was split.

Answer 6

zin = input("Typ een zinnetje: ")

def gemiddelde(s):
    return len(s.split(' '))

print (gemiddelde(zin))