Django python中的自定义管理员下拉菜单

Question

I am just a beginner in python. I have created two admin services called child and parent.

Parent - Table

id

name

type

Child - Table

pid

type

cname

In both services column "type" will be displayed in the drop down list. When creating an entry for parent, if the "type" was not chosen in the parent service. That unchosen Parent id's should shown the in the child service in dropdown Sorry for my bad english

# models.py

class Parent(models.Model):

    id = models.IntegerField(blank=False)

    type = models.ForeignKey(
        'self',
        on_delete=models.CASCADE,
        blank=True,
        null=True,
        related_name='parent_set')
   name = models.CharField(max_length=20)


class Child(models.Model):

    pid = models.IntegerField(max_length=30, blank=False)
    Type = models.ForeignKey(
         Parent,
         null=True, 
         on_delete=models.CASCADE, 
         related_name='child_set' )
    pname = models.CharField(max_length=20)

Any help would be appreciated

Answer 1

haven't tested this. Please check if this works.

class ChildAdmin(admin.ModelAdmin):
    def render_change_form(self, request, context, *args, **kwargs):
         chosen_types = Parent.objects.all().values_list('type', flat=True)
         context['adminform'].form.fields['Type'].queryset = Parent.objects.all().exclude(pk__in=chosen_types)
         return super(ChildAdmin, self).render_change_form(request, context, args, kwargs)