如何根据python中的一个方程式计算和输出多个结果？

Question

So I know how to define the function, but I don't know how to output two results where t=0 and t=1 .

Here is my code:

from math import exp
from math import pi
from math import sin


def g(t):
    a = exp(-t)
    b = sin(pi*t)
    g = a*b
    return g

t=0
print(g)

Answer 1

Call your function

g is a function. print(g) literally prints the function object. print(g(t)) prints the function g evaluated at t . So, you want this after the definition of g :

print(g(0)) # Print g evaluated at t=0
print(g(1)) # Print g evaluated at t=1

Don't reuse variable names

Don't do g = a * b . Rename it something like h . By doing that, you're redefining g to mean something different in the local scope which can get confusing. Functions are objects too!

Don't use too many intermediate variables

For your g function, you use a total of 3 intermediate variables. Normally, having intermediate variables is useful for readability. Here, it's not necessary:

def g(t):
    return exp(-t) * sin(pi * t)

(This makes it resemble the task more anyway...)

Answer 2

If you want to call your function more times in the future, you could put your arguments into a list and do this:

for arg in [0, 1]:
    print(g(arg))

Also, you can return the value directly without re-assigning to g :

def g(t):
    a = exp(-t)
    b = sin(pi*t)
    return a*b

Answer 3

Python uses tuples to return multiple values from a function:

def two_vals(): 
   return 11,22

>>> two_vals()
(11, 22)

You can use tuple expansion to assign multiple values to multiple named values:

>>> g1, g2=two_vals()
>>> g1
11
>>> g2
22

So. Rewrite your function so that it calculates both values. Return both (as a list, tuple, dict, whatever data structure) and you have your two values to print.

To fulfill this assignment however, you could just call g twice and place into a string to print:

def g(t):
    a = exp(-t)
    b = sin(pi*t)
    g = a*b
    return g

def both_g_str():
    return "g(0): {}, g(1): {}".format(g(0), g(1))