在函数外部实例化的对象。 我如何从功能访问？

Question

Tried to access as argument of the function. Not working!

object = class()

def foo(object):
    object.method

foo()

Not working!

Answer 1

I am going to be referring to object as obj since you should not be overriding built-in classes, especially since its a new-style class.

Simply put, obj within the function definition is a parameter name, not the variable obj you have assigned.

Therefore, when calling the function foo , you need to provide it the parameter it asks for. So your code should be like this:

foo(obj)

not foo()