单行无限分离循环的语法

Question

I could run something in endless loop like this:

$ while true; do foo; done

I could run something detached like this:

$ foo &

But I can't run something detached in endless loop like this:

$ while true; do foo & ; done
-bash: syntax error near unexpected token `;'

How to run an infinite detached loop in one line of shell code?

Answer 1

& is a terminator like ; , you can't mix them. Just use

while : ; do foo & done

I'd add a sleep somehwere, otherwise you'll quickly flood your system.

Answer 2

如果您想在后台运行循环，而不是每个单独的foo命令，您可以将整个内容放在括号中：

( while true; do foo; done ) &

Answer 3

You should clarify whether you want

• many copies of foo running in the background or
• a single copy of foo running within a backgrounded while loop.

choroba 's answer will do the former. To do the latter you can use subshell syntax:

(while true; do foo; done) & 

Answer 4

All good answers here already - just be aware that your original loop with @choroba's correction will successfully make a very messy infinite string of processes spawned in quick succession.

Note that there are several useful variants. You could throw a delay inside the loop like this -

while true; do sleep 1 && date & done

But that won't cause any delay between processes spawned. Consider something more like this:

echo 0 > cond   # false
delay=10        # secs

then

until (( $(<cond) )) do; sleep $delay && foo & done

or

while sleep $delay; do (( $(<cond) )) || foo & done

then make sure foo sets cond to 1 when you want it to stop spawning.

But I'd try for a more controlled approach, like

until foo; do sleep $delay; done &

That runs foo in the foreground OF a loop running in background, so to speak, and only tries again until foo exits cleanly.

You get the idea.