尝试将文本文件中的文本存储在数组 C++ 中

Question

int main(int argc, char* argv[]) {
  ifstream ifs(argv[1],ios::in); 

 if(argc!=2)  {
    cout << "Please type main.exe and file name to run the program! Please Try Again" << endl;
}

ifs.open(argv[1]);  

if (!ifs.is_open())  {
    cout << "wrong file name! please open again!" << endl;
}

char line[80]; 
char *point; 

while(ifs.getline(line,80))   //problem seem to be here
{
    cout << "line =" << line << endl;
    point = strtok(line, " ");  
       while(point!=NULL) {
          if (checkdigit(point)) 
               numberofdight++;
        else if(checkkeyword(point)) 
             keywords++;
      else  { }
  }
     cout << point <<endl;
     point = strtok(NULL, " ");
  }
}
ifs.close();

}

The program didn't pass through the while loop while(ifs.getline(line,80)) . Can someone help me, please? Pretty new to programming. Suppose to store everything from text file in array. TIA

Answer 1

So the place where you have told that problem seems to be here, I will give an answer around that.

First of I would suggest you read about getline() API to understand how it works, this will help in longer run. (Because you mentioned you are new)

As far as your use of API goes.. while(ifs.getline(line,80))

1. You can check if file is not empty using ifs.eof() . Reference for this API .
2. If your line is longer than 80 characters then also it will skip the loop.

So there are these two possibilities which might have been the reason for your control not going inside while, Debug and figure out actual reason. If still not solved, put the file which you are reading.

EDIT : Try out this code with your file. Working code for your reference. (Inspired from your problem statement code)

NOTE : Read about all APIs before using them

#include<iostream>
#include<fstream>

int main(int argc, char* argv[]) {
    ifstream ifs;

    if(argc!=2)  {
        std::cout << "Please type main.exe and file name to run the program! Please Try Again" << std::endl;
    }

    ifs.open(argv[1], std::ifstream::in);

    if (!ifs.is_open())  {
        cout << "wrong file name! please open again!" << endl;
    }

    char line[80];
    char *point; //NOT needed for my samplecode, have just kept from your code

    while(ifs.getline(line,80))   //problem seem to be here
    {
        cout << "line =" << line << endl;
        //TODO:: Write your business logic here.
    }

    ifs.close();
}