如何使用列表理解或切片来测试字符串列表是否为回文？

Question

I am trying to test if a list of strings are palindromes using list comprehension or slicing. I converted str1 to list using word_list=str1.split() . However, the palindrome test,

word=[w for w in word_list if w[0:9:1]==w[0:9:1][::-1]]

works for only the first word. Since the words have different lengths, I am wondering if there are concise way of writing the code without using common loops?

str1='avallava si padre emirime'

Answer 1

@Chris_Rands answer solved the problem. word=[w for w in word_list if w==w[::-1]]

Answer 2

The line below iterates through word_list, keeps the words which are palindromes and stores them as a list.

palindromes = [w for w in word_list if w == w[::-1]]

If world_list = ['avallava', 'si', 'padre', 'emirime'] ,

then palindromes = ['avallava', 'emirime']

Answer 3

a=['aba','abc','lil','ozx'] b=[] for i in a: if i==i[::-1]: b.append(i)

print(b)