如何根据php中的文件名打开特定文件？

Question

I need to open an HTML file which is inside nested folders.

for example:

*USERDATA\\FILES* Inside FILES- 8111,8114,8333,8585 (these are the folder names inside FILES)

I should pick up the folder 8585

Inside this FILES folder, I have 1 to 4 folders, the folder names will be in number. I should pick up the folder which has the maximum number. How to do that?

note: since it is sorted, the file with the maximum number will be at last.

Answer 1

Use scandir function and sort desc folder name.

$files2 = scandir($dir, 1); 

output :

Array
(
    [0] => somedir
    [1] => foo.txt
    [2] => bar.php
    [3] => ..
    [4] => .
)

PHP::scandir