python findall匹配全部大写的字符串

Question

I am trying to use python re.findall to match string with following conditions:

contain all uppercase letters
have numbers present sometimes

I tried

ab_list = re.findall(r'([A-Z]+)(\.\d+)', text)

but this does not return anything.

Answer 1

You can try this:

import re
s = ["ALL CAPITALS ARE ON", "Some lower, soMe not", "AGAIN, WITH PUNCTIONATION."]
final_data = [i for i in s if re.findall("^[A-Z0-9\W]+$", i)]

Output:

['ALL CAPITALS ARE ON', 'AGAIN, WITH PUNCTIONATION.']

If you are trying to find words that are all capitalized:

s = ["NOT (LOWER)", "Some lower, soMe not", "AGAIN, WITH PUNCTIONATION.", "young 10 (MODY10)"]
final_data = [b for b in [re.findall("(?<=\().*?(?=\))", i) for i in s] if b and re.findall("^[A-Z0-9\W]+$", b[0])]
final_data = [b for b in [re.findall("\(([A-Z0-9\W])\)", i) for i in s] if b]

Output:

[['LOWER'], ['MODY10']]

If you have one long string:

s = 'NOT (LOWER)Some lower, soMe notAGAIN, WITH PUNCTIONATION.young 10 (MODY10)'
final_strings = re.findall("\(([A-Z0-9\W]+)\)", s)

Output:

['LOWER', 'MODY10']

Answer 2

This will find strings containing only uppercase letters, numbers, and spaces.

re.findall('^[A-Z0-9 ]+$', text)

This will return a list containing the string if it matches, otherwise, it returns an empty list. If you just want to detect whether the whole string matches, though, it might be more straightforward to use re.match rather than re.findall . That depends on what you're ultimately trying to do.

If you want to instead find the individual words, you might want:

re.findall('([A-Z0-9]+)', text)