Python 正则表达式匹配关键字的所有变体，除非前面有大写单词

Question

I'm looking for a Python Regex to match a all variations of a keyword except if preceded by a capitalized word -> except when that capitalized word is the start of a sentence. Also excludes words between brackets.

for example:

keyword = 'public record'
string1 = 'Hello. His public records are available at city hall.' #match public records His is the start of a sentence so we ignore that it is capitalized and match
string2 = 'his records are at Newsom Public Record DataBase'      #nomatch
string3 = 'Public records may be available online'                #match Public records
string4 = '[public records](http:/....)'                          #nomatch

So far I have tried:

pattern = f'(?<!\[)(?i)\\w*{keyword}\\w*'   #Doesn't  take into account preceding capitalized words
pattern = f'(?<![A-Z][\w-]\s)(?<!\[)(?i)\\w*{keyword}\\w*' #Doesn't work for cap words > 2 chara

Answer 1

You can specify the various allowed beginnings, ie start of sentence + cap word, non-cap word or beginning of string, and then assert that the keyword follows with a lookahead:

pattern = r'(\. [A-Z]\w* |\W[^A-Z]\w* |^)(?=[pP]ublic [rR]ecord)'