[英]LibGDX: Where is the X-/Y-Coordinate of a circle?
I´m wondering how a circle is positioned. 我想知道圆形的位置。 For example the X-/Y-Coordinates of an rectangle are in the bottom left corner of itself.
例如,矩形的X / Y坐标位于其左下角。 But how does it work with a circle?
但是它如何与圆一起工作? ~Henri
〜亨利
Rectangle
position(X and Y coordinate) defined by bottom-left corner of itself. Rectangle
位置(X和Y坐标)由其左下角定义。
But in case of Circle
there is no corner or any such parameter. 但是在
Circle
情况下,没有角或任何此类参数。 Circle having center(X and Y coordinate) and radius. 具有中心(X和Y坐标)和半径的圆。
If we construct a circle with default constructor 如果我们用默认构造函数构造一个圆
Circle circle=new Circle();
In this case x,y and radius all are zero, so circle center is at at bottom-left of the screen with radius zero. 在这种情况下,x,y和半径都为零,因此圆心位于屏幕的左下角,半径为零。
X/Y coordinates of circle is it's center. 圆的X / Y坐标为中心。
Here is one of circle's constuctors. 这是圈子的构造者之一。
/** Constructs a new circle with the given X and Y coordinates and the given radius.
*
* @param x X coordinate
* @param y Y coordinate
* @param radius The radius of the circle */
public Circle (float x, float y, float radius) {
this.x = x;
this.y = y;
this.radius = radius;
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.