无法建立Hibernate SessionFactory插入更新为false

Question

Table Client Name="clients"

@OneToMany(mappedBy="clientObj", fetch=FetchType.LAZY)
private List<BookedRoom> bookedRooms;

And table Booked Room

@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
@Column(unique=true, nullable=false)
private BigInteger id;

@Column(name="accommodation")
private BigInteger accommodation;

@Column(name="account")
private BigInteger account;

@Column(length=40)
private String clients;

@Column(name="clients_id", length=40)
private String clientsId;

@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="clients", nullable=false)
@JsonBackReference 
private Client clientObj;

@Column(name="rooms_no")
private byte roomsNo;

@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="room", nullable=false)
@JsonBackReference 
private AccommodationRoom accommodationRoom;

@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="bed_preference")
@JsonBackReference 
private BedPreference bedPreferenceBean;

@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="booking", nullable=false)
@JsonBackReference 
private Booking bookingBean;

And error:

Caused by: org.hibernate.MappingException: Repeated column in mapping for entity: ba.go2balkan.pojo.BookedRoom column: clients (should be mapped with insert="false" update="false") [java] at org.hibernate.mapping.PersistentClass.checkColumnDuplication(PersistentClass.java:709) [java] at org.hibernate.mapping.PersistentClass.checkPropertyColumnDuplication(PersistentClass.java:731) [java] at org.hibernate.mapping.PersistentClass.checkColumnDuplication(PersistentClass.java:753) [java] at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:506) [java] at org.hibernate.mapping.RootClass.validate(RootClass.java:270) [java] at org.hibernate.cfg.Configuration.validate(Configuration.java:1358) [java] at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1849) [java] at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:850) [java] ... 34 more

And don't tell me to insert (insertable="false", updateble="false"). Because when I insert that than I can not read data from database or anything else. That's not solution.

Answer 1

you have

@Column(length=40)
private String clients;

and

@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="clients", nullable=false)
@JsonBackReference 
private Client clientObj;

that are trying to map the same db column (if you don't specify column name then hibernate will use field name for column mapping)...

Either give a different name to the first if it's actually another column, use insertable=false, updatable= false on the non association mapping String clients or remove that meaningless field altogether