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[英]Springboot :: Hibernate :: Unable to build Hibernate SessionFactory
[英]Unable to build Hibernate SessionFactory insert update false
表Client Name =“ clients”
@OneToMany(mappedBy="clientObj", fetch=FetchType.LAZY)
private List<BookedRoom> bookedRooms;
和桌子訂的房間
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
@Column(unique=true, nullable=false)
private BigInteger id;
@Column(name="accommodation")
private BigInteger accommodation;
@Column(name="account")
private BigInteger account;
@Column(length=40)
private String clients;
@Column(name="clients_id", length=40)
private String clientsId;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="clients", nullable=false)
@JsonBackReference
private Client clientObj;
@Column(name="rooms_no")
private byte roomsNo;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="room", nullable=false)
@JsonBackReference
private AccommodationRoom accommodationRoom;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="bed_preference")
@JsonBackReference
private BedPreference bedPreferenceBean;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="booking", nullable=false)
@JsonBackReference
private Booking bookingBean;
錯誤:
由以下原因引起:org.hibernate.MappingException:實體的映射中重復的列:ba.go2balkan.pojo.BookedRoom列:客戶端(應與org.hibernate上的insert =“ false” update =“ false”映射)[java]。 org.hibernate.mapping.PersistentClass.checkPropertyColumnDuplication(PersistentClass.java:731)上的mapping.PersistentClass.checkColumnDuplication(PersistentClass.java:709)[java]在org.hibernate.mapping.PersistentClass.checkColumnDuplication(PersistentClass.java: 753)[java]在org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:506)[java]在org.hibernate.mapping.RootClass.validate(RootClass.java:270)[java]在org.hibernate。 cfg.Configuration.validate(Configuration.java:1358)[java]在org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1849)[java]在org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl $ 4.perform (EntityManagerFactoryBuilderImpl.java:850)[java] ...另外34個
並且不要告訴我要插入(insertable =“ false”,updateble =“ false”)。 因為當我插入它時,我無法從數據庫或其他任何東西讀取數據。 那不是解決方案。
你有
@Column(length=40)
private String clients;
和
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="clients", nullable=false)
@JsonBackReference
private Client clientObj;
試圖映射同一數據庫列(如果您未指定列名,則休眠將使用字段名進行列映射)...
如果實際上是另一列,請給第一個起一個不同的名稱,在非關聯映射String clients
上使用insertable=false, updatable= false
或完全刪除無意義的字段
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