[英]How to process and combine data.frames in a list with faster way
Finally, I come to an issue that very slow data processing and appending rows of multiple data.frames
.最后,我遇到了一个问题,即数据处理速度非常慢并附加多个
data.frames
行。 I use lapply
and dplyr
combination for data processing.我使用
lapply
和dplyr
组合进行数据处理。 OTH, the process becomes very slower as I have 20000 rows in each data frame multiplied with 100 files in the directory. OTH,该过程变得非常慢,因为我在每个数据框中有 20000 行与目录中的 100 个文件相乘。
Currently this is a huge bottle neck for me as even after lapply
process finishes I don't have enough memory to bind_rows
process.目前,这对我来说是一个巨大的瓶颈,因为即使在
lapply
进程完成后,我也没有足够的内存来进行bind_rows
进程。
Here is my data processing method,这是我的数据处理方法,
files <- list.files("file_directory",pattern = "w.*.csv",recursive=T,full.names = TRUE)
library(tidyr)
library(dplyr)
data<- lapply(files,function(x){
tmp <- read.table(file=x, sep=',', header = T,fill=F,skip=0, stringsAsFactors = F,row.names=NULL)%>%
select(A,B, C)%>%
unite(BC,BC,sep='_')%>%
mutate(D=C*A)%>%
group_by(BC)%>%
mutate(KK=median(C,na.rm=TRUE))%>%
select(BC,KK,D)
})
data <- bind_rows(data)
I am getting an error which says,我收到一个错误,上面写着,
“Error: cannot allocate vector of size ... Mb” ...
“错误:无法分配大小为 ... Mb 的向量” ...
Depends on how much left in my ram.取决于我的 ram 中还剩多少。 I have 8 Gb ram but seems still struggling;(
我有 8 Gb 内存,但似乎仍在挣扎;(
I also tried do.call but nothing changed!我也试过do.call但没有任何改变! Who is my friendly function or approach for this issue?
谁是我对这个问题的友好功能或方法? I use R version 3.4.2 and dplyr 0.7.4.
我使用 R 版本 3.4.2 和 dplyr 0.7.4。
I can't test this answer since there's no reproducible data but I guess it could be something like the following, using data.table:我无法测试这个答案,因为没有可重复的数据,但我想它可能类似于以下内容,使用 data.table:
library(data.table)
data <- setNames(lapply(files, function(x) {
fread(x, select = c("A", "B", "C"))
}), basename(files))
data <- rbindlist(data, use.names = TRUE, fill = TRUE, id = "file_id")
data[, BC := paste(B, C, sep = "_")]
data[, D := C * A]
data[, KK := median(C, na.rm = TRUE), by = .(BC, file_id)]
data[, setdiff(names(data), c("BC", "KK", "D")) := NULL]
Using ldply
from the plyr
package would eliminate the need to bind the list after processing as it will output a data.frame使用
ldply
包中的plyr
将消除处理后绑定列表的需要,因为它将输出一个 data.frame
library(tidyr)
library(dplyr)
library(plyr)
files <- list.files("file_directory", pattern = "w.*.csv", recursive = TRUE, full.names = TRUE)
data<- ldply(files, function(x){
read.table(file=x, sep=',', header = TRUE, fill = FALSE, skip = 0, stringsAsFactors = FALSE, row.names = NULL) %>%
select(A, B, C) %>%
unite(BC, BC, sep='_') %>%
mutate(D = C * A) %>%
group_by(BC) %>%
mutate(KK = median(C, na.rm = TRUE)) %>%
select(BC, KK, D)
})
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