如何在mysqli表列中一个接一个地列出所有相关数据

Question

How do i list out all related data in mysqli database one after the other? I tried these code below. It outputs unknown result:

<?php
    include_once "init.php";
    $sqli = mysqli_query($conn, "SELECT * FROM books WHERE book='1905515'");
    $productCount = mysqli_num_rows($sqli);
    if ($productCount > 0) {
        while($fow = mysqli_fetch_array($sqli)){
            foreach ($fow as $item) {
                $id = $item['item_name'];
            }
        }
    }
    echo '' . $id . '';
?>

Answer 1

when you call echo '' . $id . ''; echo '' . $id . ''; $id doesn't exist anymore because $id exists only in foreach scope.

Try this :

include_once "init.php";
$sqli = mysqli_query($conn, "SELECT * FROM books WHERE book='1905515'");
$productCount = mysqli_num_rows($sqli);
if ($productCount > 0) {
    while($fow = mysqli_fetch_array($sqli)){
        echo '' . $fow['item_name'] . '';
    }
}

?>