PHP，HTML和MySqli-如何在一个表行中显示特定列的所有数据

Question

I have a database table called names . I have 2 columns there - "id" and "name". In the column "name" I have some data like:

Inna

 Petia 

Vaska

Kote

Pepa

I want this data to be shown in a html table like this:

 <table> <tr> <td>Inna</td> <td>Petia</td> <td>Vaska</td> <td>Kote</td> <td>Pepa</td> <tr> </table> 

My PHP code is:

<?php
$q= mysqli_query($db, 'SELECT * FROM names');

echo '<table>';

while ($row = mysqli_fetch_assoc($q)){
echo '<tr>';
foreach($row as $value) {   
        echo "<td>$value</td> "; 
    }  
echo ' </tr>';
}

but this did not work for me!

Answer 1

try this:

echo '<table>';

while ($row = mysqli_fetch_assoc($q)){
    echo '<tr>';
    //foreach($row as $value) {   
        echo "<td>" . $row['name'] . "</td>"; 
    //    }  
    echo '</tr>';
}

Answer 2

<?php
$q= mysqli_query($db, 'SELECT * FROM names');
echo '<table>';
echo '<tr>';
while ($row = mysqli_fetch_assoc($q)){
foreach($row as $value) {   
    echo "<td>$value</td> "; 
}  
}
echo ' </tr>';

This is the solution of my problem: I just has to put

echo '<tr>';
echo '</tr>';

outside the while!