PHP MySQLi 如何在 html 表中显示用户个人资料图像？

Question

I'm trying to show the profile image of the user in HTML table where i list the rest of user's info. But i can't get it to show, instead i'm getting Broken Image in the table. And if i right click on the "broken image" and choose "Open image in new tab" i can see the path of the image and the link to the image Parent Directory I'm uploading the the path of the image to the database and storing the image to a folder ( images/profilepic ).

Can someone help me please? Thanks a lot!

This is my insert.php code:

<?php
$server = "localhost";
$user = "root";
$pass = "";
$dbname = "employees";

// Create connection
$conn = mysqli_connect($server, $user, $pass, $dbname);

// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}

$profile_file = basename($_FILES['profileimg']['name']);
$profile_path = "images/profilepic/$profile_file";
$profile_file = mysqli_real_escape_string($conn, $profile_file);

move_uploaded_file($_FILES['profileimg']['tmp_name'], $profile_path);


$sql = "INSERT INTO addemployees (profileimg)
        VALUES ('$profile_file')";

if (mysqli_query($conn, $sql)) {
  header("location: employees.php");

} else {
    echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}

//Close the connection
mysqli_close($conn);

?>

And this is where i'm showing it:

<table id="dtBasicExample" class="table table-bordered table-hover text-center">
                             <thead>
                               <tr class="naslov">
                                   <th class="th-sm">ID:</th>
                                   <th class="th-sm">Profile Picture:</th>
                                   <th class="th-sm">First Name:</th>
                                   <th class="th-sm">Last Name:</th>
                                   <th class="th-sm">DOB:</th>
                                   <th class="th-sm">EMBG:</th>
                                   <th class="th-sm">Work Position:</th>
                                   <th class="th-sm">Address:</th>
                                   <th class="th-sm">Contract:</th>
                                   <th class="th-sm" colspan="2">Опции:</th>
                               </tr>
                            </thead>

                            <tbody id="myTable">

                          <?php

                              $conn = mysqli_connect("localhost", "root", "", "employees");

                            if (!$conn) {
                            die("Connection failed: " . mysqli_connect_error());
                            }

                              $sql = "SELECT * from addemployees";
                              $result = $conn-> query($sql);

                              if ($result-> num_rows > 0) {
                             while ($row = $result-> fetch_assoc()) {




                               echo "<tr>
                                      <td>".$row['id']."</td>
                                      <td><img src='images/profilepic/'". $row['profileimg'] ."' border=0 class='tile' id='profileimg'></td>
                                      <td>".$row['fname']."</td>
                                      <td>".$row['lname']."</td>
                                      <td>".$row['dob']."</td>
                                      <td>".$row['embg']."</td>
                                      <td>".$row['workposition']."</td>
                                      <td>".$row['address']."</td>
</tr>";


                          }

                            echo "</table>";
                          }
                            else {
                            echo "0 results";
                          }

                        $conn-> close();

                              ?>

                              </tbody>

Answer 1

Remove the single quote before the variable in your <img src :

<td><img src='images/profilepic/". $row['profileimg'] ."'
                                ^-- remove the ' here   ^-- but leave this one

The way you have it now, your variable is outside the src attribute:

// if $row['profileimg'] is image.jpg:
<img src='images/profilepic/'". $row['profileimg'] ."' border=0>

// will become:
<img src='images/profilepic/'image.jpg' border=0>
//                          ^-- end of the src='' argument