如何使用带有 boost 128 位整数的 C++ max 函数

Question

If I have the following code:

#include <boost/multiprecision/cpp_int.hpp>
using namespace boost::multiprecision


int main()
{
    int128_t a = Func_a()
    int128_t b = Func_b()

    std::cout << std::max(a, b) << std::endl;
    return 0;
}

And if I compile using g++ on Ubuntu, I get the following error:

error: cannot convert 'const boost::multiprecision::number >' to 'int64 {aka long long int}' in assignment

What is the proper way to compare two int128_t numbers to see which one is greater?

EDIT: I am using std::max.

Answer 1

Your code (except for missing semicolons) compiles and runs without error.

However, according to your compiler message, I'm suspecting that in

int128_t a = Func_a(); // are you really sure it is int128_t?

the left-hand side is not a boost::multiprecision::int128_t , since the compiler says it is a int64.