在python中添加了多个字典

Question

i have 6 dict like this

dict1
dict2
dict3
dict4
dict5
dict6

now I want all of this in one dict. so I used this

dict1.update({'dict2':dict2}) 
dict3.update({'dict1':dict1})
dict4.update({'dict4':dict3})
dict5.update({'dict5':dict4})                           
dict6.update({'dict6':dict5})

at last dict6 contains all value but it's not formatted correctly and it's not the pythonic way to do it

I want to improve this any suggestions

right now I'm getting like this but I don't want like this

{"main_responses": {"dict1": {"dict2": {"dict3": {"dict4": {"dict5": {}}}}}}}

i want

{"main_responses":{ "dict1": {dict1_values}, "dict2": {dict2_values}..... and so on

Answer 1

Try this:

from itertools import chain
d = chain.from_iterable(d.items() for d in (ada_dict, 
                                        wordpress_version_dict,
                                        drupal_version_dict,
                                        ssl_dict,
                                        link_dict,
                                        tag_dict)) 

api_response = {'api_response':d}

---

Or this, using reduce :

d = reduce(lambda x,y: dict(x, **y), (ada_dict, 
                                  wordpress_version_dict,
                                  drupal_version_dict,
                                  ssl_dict,
                                  link_dict,
                                  tag_dict))

api_response = {'api_response':d}

Answer 2

If you want add all dict in a single one "newDict", Be carrefull if several keys exist in multiple Dict :

ada_dict={'k1':'v1'}
wordpress_version_dict={'k2':'v2'}
drupal_version_dict={'k3':'v3'}
ssl_dict={'k4':'v4'}
link_dict={'k5':'v5'}
tag_dict={'k5':'v5'}

newDict={}
newDict.update( (k,v) for k,v in ada_dict.iteritems() if v is not None)
newDict.update( (k,v) for k,v in wordpress_version_dict.iteritems() if v is not None)
newDict.update( (k,v) for k,v in drupal_version_dict.iteritems() if v is not None)
newDict.update( (k,v) for k,v in ssl_dict.iteritems() if v is not None)
newDict.update( (k,v) for k,v in link_dict.iteritems() if v is not None)
newDict.update( (k,v) for k,v in tag_dict.iteritems() if v is not None)

print {'api_response':newDict}

https://repl.it/ND3p/1

Answer 3

Giving a very similar example of my own based on your requirements:

>>> d1 = {'a':1}
>>> d2 = {'b':2}
>>> d3 = {'c':3}
>>> d4 = {'d':4}

#magic happens here
>>> d = {'d1':d1 , 'd2':d2, 'd3':d3, 'd4':d4}
>>> d
=> {'d1': {'a': 1}, 'd2': {'b': 2}, 'd3': {'c': 3}, 'd4': {'d': 4}}

Since you do not have all the dictionaries that you want added in one place, this is about as easy as it gets.

In case you want to add another key to your collection of all dictionaries ( d here), do:

>>> out = {'api_responses': d}

#or in one step if you do not want to use `d`
>>> out = {'api_responses': {'d1':d1 , 'd2':d2, 'd3':d3, 'd4':d4}}

>>> out
=> {'api_responses': {'d1': {'a': 1}, 'd2': {'b': 2}, 'd3': {'c': 3}, 'd4': {'d': 4}}}

Answer 4

please add more comment to your post, but as I see you need something like , is not it ?

>>> foo=lambda dest, src, tag: [dest.update({tag:i}) for i in src]
>>> x={1:1}
>>> y={2:2}
>>> foo(x, y, "tag")
[None]
>>> x
{1: 1, 'tag': 2}
>>> y
{2: 2}

Answer 5

这是否有助于获得所需的输出？

   new_dict=dict(ada_dict.items()+wordpress_version_dict.items() +drupal_version_dict.items()+ssl_dict.items()+link_dict.items()+tag_dict.items())

Answer 6

 a =[ada_dict,
wordpress_version_dict,
drupal_version_dict,
ssl_dict,
link_dict,
tag_dict]

 c= {}

for i in a:
    c.update({i:i})

print c
{'ada_dict': 'ada_dict',
 'drupal_version_dict': 'drupal_version_dict',
 'link_dict': 'link_dict',
 'ssl_dict': 'ssl_dict',
 'tag_dict': 'tag_dict',
 'wordpress_version_dic': 'wordpress_version_dic'}
d={}
d.update({"api_responses":c})
print d

{'api_responses': {'ada_dict': 'ada_dict',
  'drupal_version_dict': 'drupal_version_dict',
  'link_dict': 'link_dict',
  'ssl_dict': 'ssl_dict',
  'tag_dict': 'tag_dict',
  'wordpress_version_dic': 'wordpress_version_dic'}}