我不明白结果

Question

I thought result will be int parameter a : 3 3

but result was

why result is it?

Answer 1

Where you call "cout << "int\\t" << TestFunction(3) << endl;" it needs to evaluate the function call first, before it can print out "int\\t (returned value)" The only way it will know what to print out is by running the function. When the function runs, it prints out "paramater a :". The three is then returned, and the second cout statement can be performed: (int\\t)

Answer 2

Ready steps

1. Ready to Print : "int (value)"
2. TestFunc is called.
3. "parameter a: 3" is printed.
4. TestFunc returns value "3"
5. Ready to Print : "int (value)" --> Print : "int 3"