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在熊猫数据框中的一个列中有多个值时如何计算值计数

[英]how to calculate value counts when we have more than one value in a colum in pandas dataframe

df, df

Name
Sri
Sri,Ram
Sri,Ram,kumar
Ram

I am trying to calculate the value counts for each value. 我正在尝试计算每个值的值计数。 I am not getting my output when using 使用时我没有得到输出

 df["Name"].values_count()

my desired output is, 我想要的输出是

 Sri     3
 Ram     3
 Kumar   1

split the column, stack to long format, then count : split列, stack为长格式,然后count

df.Name.str.split(',', expand=True).stack().value_counts()

#Sri      3
#Ram      3
#kumar    1
#dtype: int64

Or maybe: 或者可能:

df.Name.str.get_dummies(',').sum()

#Ram      3
#Sri      3
#kumar    1
#dtype: int64

Or concatenate before value_counts : 或在value_counts之前连接:

pd.value_counts(pd.np.concatenate(df.Name.str.split(',')))

#Sri      3
#Ram      3
#kumar    1
#dtype: int64

Timing : 时间

%timeit df.Name.str.split(',', expand=True).stack().value_counts()
#1000 loops, best of 3: 1.02 ms per loop

%timeit df.Name.str.get_dummies(',').sum()
#1000 loops, best of 3: 1.18 ms per loop

%timeit pd.value_counts(pd.np.concatenate(df.Name.str.split(',')))
#1000 loops, best of 3: 573 µs per loop

# option from @Bharathshetty 
from collections import Counter
%timeit pd.Series(Counter((df['Name'].str.strip() + ',').sum().rstrip(',').split(',')))
# 1000 loops, best of 3: 498 µs per loop

# option inspired by @Bharathshetty 
%timeit pd.value_counts(df.Name.str.cat(sep=',').split(','))
# 1000 loops, best of 3: 483 µs per loop

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