删除列表向量中的元素并显示当前列表

Question

I am trying to use a vector of lists to store information and then delete the middle item in the lists and print the list again. I am not sure how to access the individual variables of the lists stored in vector, or how to delete the element.

I am trying to delete the element 'puppy' from the list.

#include <iostream>
#include <string>
#include <vector>
#include <list>
using namespace std;

int main() {

    vector<list<string>> hashT;
    hashT.resize(3);
    int index = 0;

    hashT[0].push_back("hello");
    hashT[0].push_back("Puppy");
    hashT[0].push_back("friend");

    typename list<string>::iterator it = hashT[0].begin();

    for (; it != hashT[0].end(); ++it)
    {
        index = 0;
        //print lists?
        cout << *it;
        //delete puppy?
        hashT[0].erase(hashT[0].begin() + index)
        //print list?
        index++;
    }


    return 0;
}

Current Code-

    #include <iostream>
#include <string>
#include <vector>
#include <list>
using namespace std;

int main() {

    vector<list<string>> hashT;
    hashT.resize(3);
    int index = 0;

    hashT[0].push_back("hello");
    hashT[0].push_back("Puppy");
    hashT[0].push_back("friend");

    typename list<string>::iterator it = hashT[0].begin();

    for (; it != hashT[0].end(); ++it)
    {

        if(*it == "Puppy")
        {
            hashT[0].erase(it);
        }
    }

    typename list<string>::iterator it2 = hashT[0].begin();

        for (; it2 != hashT[0].end(); ++it2)
        {
            cout << *it2;
        }


    return 0;
}

It is still printing all 3 values.

Answer 1

#include <iostream>
#include <string>
#include <vector>
#include <list>
using namespace std;

int main() {

    vector<list<string>> hashT;
    hashT.resize(3);


    hashT[0].push_back("hello");
    hashT[0].push_back("Puppy");
    hashT[0].push_back("friend");

    typename list<string>::iterator it = hashT[0].begin();

    for (; it != hashT[0].end(); it++)
    {
        if(*it == "Puppy")
        {
            hashT[0].erase(it);
            break;
        }
    }

    typename list<string>::iterator it2 = hashT[0].begin();

    for (; it2 != hashT[0].end(); ++it2)
    {
        cout << *it2;
    }
    cout << endl;


    return 0;
}