在中间逗号之间将字符串拆分为两个？

Question

I want to split a string into 2 parts based on the middle comma.

• There can be an unlimited amount of commas
• Assume there will be an odd number of commas at all time

From:

"1, 4, a, fdsa, 53, dfs, sdfg, klk"

To:

"1, 4, a, fdsa" and "53, dfs, sdfg, klk"

Answer 1

Some basic arithmetic:

splitstring = mystring.split(',')
print(','.join(splitstring[:len(splitstring)//2]) + ' and ' + ','.join(splitstring[len(splitstring)//2:]))

In case you want to eliminate extra spaces from the original string after the middle comma you can just strip them, so add to each join statement:

','.join(...).strip()

Answer 2

Regards. I will use your string as example :

S = "1, 4, a, fdsa, 53, dfs, sdfg, klk"

Assuming that the number of , will be odd. So, my idea is to locate the middle , (this would be the (n+1)th , ). To do this, we can apply the string method .find .

S.find(',') will return 1 . (since the first , is at index 1 )

S.find(',', 2) will return 4 . (since after the 3rd character on your string, the first , is at index 4 )

Let the number of , in the string be 2n+1 . Since you don't know the location of the middle , (for other strings) you can use loop as many as (n+1) times to locate the index of the middle , . You may use S.count(',') to find the number of , 's (this will be n ).

Let the location (or index) be m . So that after this, you can create two strings : A=S[0:m-1]; and B=S[m+1:]; to produce the desired split.

Hope this helps.

Answer 3

Just splitting and rejoining the first half.

>>> s = '1, 4, a, fdsa, 53, dfs, sdfg, klk'

>>> *a, b = s.split(', ', s.count(',') // 2 + 1)
>>> ', '.join(a), b
('1, 4, a, fdsa', '53, dfs, sdfg, klk')

Answer 4

Let your sting be input_str, then

s = input_str.split(',')
string_length = len(s)
print(','.join(s[0:string_length//2]) +" and " + ','.join(s[string_length//2:]))

will print what you need.