在第二次出现逗号时拆分字符串

Question

My string is like below:

Str=S1('amm','string'),S2('amm_sec','string'),S3('amm_','string')

How can I Split the string so that my str_list item becomes:

Str_List[0]=S1('amm','string')
Str_List[1]=S2('amm_sec','string') 
...

If I use Str.split(',') then the output is:

Str_List[0]=S1('amm'
...

Answer 1

you can use regex with re in python

import re
Str = "S1('amm','string'),S2('amm_sec','string'),S3('amm_','string')"
lst = re.findall("S\d\(.*?\)", Str)

this will give you:

["S1('amm','string')", "S2('amm_sec','string')", "S3('amm_','string')"]

to explain the regex a little more:

S first you match 'S'

\\d next look for a digit

\\( then the '(' character

.*? with any number of characters in the middle (but match as few as you can)

\\) followed by the last ')' character

you can play with the regex a little more here

Answer 2

My first thought would be to replace ',S' with ' S' using regex and split on spaces.

import re
Str = re.sub(',S',' S',Str)
Str_list = Str.split()