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从R数据框中的每一行中删除重复项

[英]Remove duplicates from each row in R dataframe

I have a dataframe with 1209 columns, and 27900 rows. 我有一个具有1209列和27900行的数据框。

For each row there are duplicated values scatter around the columns. 对于每一行,重复的值分散在列周围。 I have tried transposing the dataframe and remove by columns. 我尝试过转置数据框并按列删除。 But it crashes. 但是它崩溃了。

After I transpose I used: 转置后,我使用了:

for(i in 1:ncol(df)){

        #replicate column i without duplicates, fill blanks with NAs
        df <-  cbind.fill(df,unique(df[,1]), fill = NA)
        #rename the new column
        colnames(df)[n+1] <- colnames(df)[1]
        #delete the old column
        df[,1] <- NULL
}

But no result so far. 但是到目前为止没有结果。

I would like to know if anyone has any idea. 我想知道是否有人有任何想法。

Best 最好

As I understand you would like to replace duplicated values in each column with NA? 据我了解,您想用NA替换每列中的重复值吗?

this can be done in several ways. 这可以通过几种方式来完成。

First some data: 首先一些数据:

set.seed(7)
df <- data.frame(x = sample(1: 20, 50, replace = T),
                 y = sample(1: 20, 50, replace = T),
                 z = sample(1: 20, 50, replace = T))
head(df, 10)
#output
    x  y  z
1  20 12  8
2   8 15 10
3   3 16 10
4   2 13  8
5   5 15 13
6  16  8  7
7   7  4 20
8  20  4  1
9   4  8 16
10 10  6  5

with purrr library: 与purrr库:

library(purrr)
map_dfc(df, function(x) ifelse(duplicated(x), NA, x))
#output
# A tibble: 50 x 3
       x     y     z
   <int> <int> <int>
 1    20    12     8
 2     8    15    10
 3     3    16    NA
 4     2    13    NA
 5     5    NA    13
 6    16     8     7
 7     7     4    20
 8    NA    NA     1
 9     4    NA    16
10    10     6     5
# ... with 40 more rows

with apply in base R 与适用于基数R

as.data.frame(apply(df, 2, function(x) ifelse(duplicated(x), NA, x)))

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