bash：如何比较字符串与数字和字母？

Question

I have an array the contains element like 1617b, 1516a and the like. I want to echo the elements in descending order-meaning the ones with the greatest number chars in them, and if identical the ones with bigger letter. Any idea on how to do this? Will a simple "if" work? As in:

if [[ ${array[$j]}>${array[$j+1]} ]]; then
     .
     .
     .

tnx in advance

Answer 1

here is one way

$ ar=(1234a 2345b 1234c 4444d)
$ sorted=$(printf "%s\n" ${ar[@]} | sort | xargs)
$ echo $sorted

1234a 1234c 2345b 4444d

for descending order add -r flag to sort

if you want your sorted values back to an array

$ sorted_ar=($(printf "%s\n" ${ar[@]} | sort))
$ echo ${sorted_ar[@]}