[英]FileNotFoundException in onActivityResult
I am trying to browse only two file-types: images or pdf. 我正在尝试仅浏览两种文件类型:图像或pdf。
Here is the source: 来源如下:
String[] permissions = new String[]{Manifest.permission.READ_EXTERNAL_STORAGE};
myPermissions =new MyPermissions(TestDialog.this, 0, permissions);
MyPermissions.EventHandler permHandler = new MyPermissions.EventHandler() {
@Override
public void handle() {
Intent intent = new Intent();
intent.setAction(Intent.ACTION_GET_CONTENT);
intent.setType("application/pdf");
intent.setType("image/jpeg");
startActivityForResult(intent, 0);
}
};
myPermissions.doIfHasPermissions(permHandler);
Here is a my onActivityResult
source: 这是我的onActivityResult
源:
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (resultCode == RESULT_OK) {
String url = data.getData().getPath();
File myFile = new File(url);
Log.e("base64 ", getStringFile(myFile));
}
super.onActivityResult(requestCode, resultCode, data);
}
public String getStringFile(File f) {
InputStream inputStream = null;
String encodedFile = "", lastVal;
try {
inputStream = new FileInputStream(f.getAbsolutePath());
byte[] buffer = new byte[10240];//specify the size to allow
int bytesRead;
ByteArrayOutputStream output = new ByteArrayOutputStream();
Base64OutputStream output64 = new Base64OutputStream(output, Base64.DEFAULT);
while ((bytesRead = inputStream.read(buffer)) != -1) {
output64.write(buffer, 0, bytesRead);
}
output64.close();
encodedFile = output.toString();
} catch (FileNotFoundException e1) {
e1.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
lastVal = encodedFile;
return lastVal;
}
I would like to convert the selected file to Base64, but I get a FileNotFoundException
. 我想将所选文件转换为Base64,但得到FileNotFoundException
。 Does anyone have any idea what am I doing wrong? 有人知道我在做什么错吗?
I try to browse only two type files,images or pdf 我尝试仅浏览两种类型的文件,图像或pdf
Your code has nothing much to do with files. 您的代码与文件无关。 It uses ACTION_GET_CONTENT
, which allows the user to choose a piece of content. 它使用ACTION_GET_CONTENT
,它允许用户选择内容。
String url = data.getData().getPath();
This line is useless, unless the Uri
has a scheme of file
. 除非Uri
有一个file
方案,否则此行是无用的。 Most likely, it has a scheme of content
. 它很可能具有content
计划。
Stop using File
and FileInputStream
. 停止使用File
和FileInputStream
。 Instead, get an InputStream
from a ContentResolver
(from getContentResolver()
) and its openInputStream()
method. 而是从ContentResolver
(从getContentResolver()
)及其openInputStream()
方法获取InputStream
。 You can pass in the Uri
, and you will get an InputStream
regardless of whether the Uri
scheme is file
or content
. 您可以传入Uri
,无论Uri
方案是file
还是content
,您都将获得InputStream
。
Also note that your app is likely to crash with an OutOfMemoryError
, except for fairly small files, as you will not have enough heap space to perform this conversion. 还要注意,您的应用可能会因OutOfMemoryError
崩溃,但文件很小,因为您没有足够的堆空间来执行此转换。
Have a look at 看一下
Uri uri = data.getData();
Then try to log the value of uri.toString(). 然后尝试记录uri.toString()的值。
You will see that it starts with "content//....". 您将看到它以“ content // ....”开头。
Do not try to find a file. 不要尝试查找文件。
Instead of a FileInputStream use an InputStream. 代替FileInputStream使用InputStream。
InputStream inputStream = getContentResolver().openInputStream(uri);
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