无法从html分别提取数字和文本

Question

From the html code below I want to get the number separately & the text separately, I am able to get the number but for text it's giving error as shown below. (Note: it is in for loop , for few links its working as the split(b'.')[1] is matching, if the index is not found its giving error).

Error:

Traceback (most recent call last):
  File "C:/Users/Computers Zone/Google Drive/Python/SANDWICHTRY.py", line 49, in <module>
    sandwich=soup.find('h1',{'class':'headline'}).encode_contents().strip().split(b'.')[1].decode("utf-8")
IndexError: list index out of range

HTML code:

<h1 class="headline ">1. Old Oak Tap BLT</h1>

Ny code:

soup=BeautifulSoup(pages,'lxml').find('div',{'id':'page'})
rank=soup.find('h1',{'class':'headline'}).encode_contents().strip().split(b'.')[0].decode("utf-8")
print (rank)
sandwich=soup.find('h1',{'class':'headline'}).encode_contents().strip().split(b'.')[1].decode("utf-8")
print(sandwich)

Answer 1

This error occures, when there is no . in your headline string, ie the second element does not exist.

To solve this, get the results, split the string, but do not assume that there are always two elements:

from bs4 import BeautifulSoup

pages = '<h1 class="headline">1. Old Oak Tap BLT</h1>'

soup = BeautifulSoup(pages, 'lxml')
titles = soup.find('h1', {'class': 'headline'}).encode_contents().split(b'.')

for text in titles:  # go through all existing list elements
    print(text.decode("utf-8").strip())

Or check for 2 elements in your list prior to reading the elements, eg:

if len(titles) == 2:
    rank = titles[0].decode("utf-8").strip()
    sandwich = titles[1].decode("utf-8").strip()