正则表达式从段落中分别提取标题和文本

Question

I wanted to separate out the header and it's corresponding text, separated by a delimiter colon from a paragraph.

Example Paragraph , "INCIDENTS: Quick fox ran over. A plane drove the head. RESULT AND CONCLUSION: I got headache, and fever"

Output I expect : [('INCIDENTS', 'Quick fox ran over. A plane drove the head'), ('RESULT AND CONCLUSION', 'I got headache, and fever')]

I am using python and tried with re.findall(r'([AZ]+:)(.*?)\\.', <paragraph>) . But I haven't got the expected output.

Any help is appreciated.....

Answer 1

You can use

re.findall(r'\b([A-Z]+(?:\s+[A-Z]+)*):\s*(.*?)(?=\s*\b(?:[A-Z]+(?:\s+[A-Z]+)*):|$)', text)

See the regex demo

Details

• \\b - word boundary
• ([AZ]+(?:\\s+[AZ]+)*) - Group 1: an uppercase word and then zero or more whitespace-separated uppercase words
• : - a colon
• \\s* - 0 or more whitespaces
• (.*?) - Group 2: any zero or more chars as few as possible
• (?=\\s*\\b(?:[AZ]+(?:\\s+[AZ]+)*):|$) - up to the 0 or more whitespaces, a word boundary, an uppercase word and then zero or more whitespace-separated uppercase words, or end of string.