对角遍历二维数组

Question

I have to iterate through an 2D array of chars. I already have the code to iterate / but I'm lost when it comes to .

Here is my 2d array:

a,v,i,o,n,l
t,o,t,o,l,l
m,a,r,c,o,e
s,a,g,r,c,i
o,e,n,z,o,g
s,t,r,a,r,u

I already have:

a
tv
moi
....

and I need:

l
nl
ole
....

Here is the code to iterate / :

int size = 6;

for (int k = 0 ; k < size ; k++) {
    for (int j = 0 ; j <= k ; j++) {
        int i = k - j;
        System.out.print( lista[i][j] + " " );
    }
    System.out.println();
}

for (int k = size - 2 ; k >= 0 ; k--) {
    for (int j = 0 ; j <= k ; j++) {
        int i = k - j;
        System.out.print(lista[size - j - 1][size - i - 1] + " " );
    }
    System.out.println();
}

Answer 1

Try this:

public class Matrix {
    public static void main(String[] args) {
        char[][] arr = {
                { 'a', 'v', 'i', 'o', 'n', 'l' }, 
                { 't', 'o', 't', 'o', 'l', 'l' },
                { 'm', 'a', 'r', 'c', 'o', 'e' }, 
                { 's', 'a', 'g', 'r', 'c', 'i' }, 
                { 'o', 'e', 'n', 'z', 'o', 'g' },
                { 's', 't', 'r', 'a', 'r', 'u' } };
        for (int n = -arr.length; n <= arr.length; n++) {
            for(int i = 0; i < arr.length; i++){
                if((i-n>=0)&&(i-n<arr.length)){
                    System.out.print(arr[i][i-n]);
                }
            }
            System.out.println();
        }
    }
}

Answer 2

You can use your own code. The only thing you need to do is transpose your matrix first. I have written and tested it for you. myArray is the array you gave us as input and yourArray is the one you need to use in for your code as lista.

for (int i = 5; i >= 0; i--) {
    for (int j = 0; j <= 5; j++) {
       yourArray[5 - i][j] = myArray[j][i];
    }
}