[英]network communication using python and socket
I have succesfully made a code which starts a server which can be connected by other devices on my LAN with the CMD command telnet hostname port
when the new "client" enters a word and presses enter the word is then sent back to them through the server. 我成功编写了一个代码,启动了一个服务器,当新的“客户端”输入一个单词并按下输入的单词,然后通过服务器发送回给他们时,该服务器可以通过CMD命令
telnet hostname port
连接到我的LAN上的其他设备。 。 My question is if i connected 2 devices to the server how would i get the message to get sent from one to the server then back to the other. 我的问题是,如果我将2台设备连接到服务器,我如何将消息从一台发送到服务器,然后又发送回另一台。 Like a messaging programme.
就像一个消息传递程序。 The code i have used is shown below
我使用的代码如下所示
import socket
import sys
from _thread import *
host = ''
port = 5555
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
try:
s.bind((host, port))
except socket.error as e:
print(str(e))
s.listen(5)
print('Waiting for a connection.')
def threaded_client(conn):
conn.send(str.encode('Welcome, type your info\n'))
final_char = ""
while True:
data = conn.recv(2048)
char = data.decode("utf-8")
print(data)
if data != b'\r\n':
final_char += char
print(final_char)
else:
reply = 'Server output: '+ final_char+"\n"
if not data:
break
conn.sendall(str.encode(reply))
final_char = ""
conn.close()
while True:
conn, addr = s.accept()
print(addr)
print(conn)
print('connected to: '+addr[0]+':'+str(addr[1]))
start_new_thread(threaded_client,(conn,))
Not an actual implementation, but some theory: 不是实际的实现,而是一些理论:
You need to keep a list of all the clients you have an active connection to: 您需要保留与以下设备建立活动连接的所有客户端的列表:
while ( true )
client = server.accept()
clientList.add(client)
startThread(client)
Then in the thread 然后在线程中
while ( true )
data = connection.receive()
for client in clientList
client.sendall( data )
Take a look at ZQM the python library works perfect and it has already implemented what you need using sockets internally. 看一下ZQM,python库可以完美地工作,它已经在内部使用套接字实现了您所需要的。 https://learning-0mq-with-pyzmq.readthedocs.io/en/latest/
https://learning-0mq-with-pyzmq.readthedocs.io/en/latest/
Take a look at their publisher / subscriber message pattern. 看一下他们的发布者/订阅者消息模式。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.