Unix Shell，基于日期对文件执行命令

Question

I have an application server that produces daily log on the following format:

access_log.{Y-m-d}

So I want to execute a command in a way like this:

tail -f access_log.{+%Y-%m-%d}

Is there any way to do a in single line without creating variables ?

Answer 1

在这里找到

tail -f "access_log.$(date '+%Y-%m-%d')"