如何用c ++编写程序以解决无法事先知道从其读取的数据文本文件中包含多少行的问题？

Question

I've written a program to calculate the chi-squared value using data given. However, I need to write it so that my program can account for not knowing how many lines are in the text file it is reading from. If I define my structure points as point thePoints[1000], (ie greater than the number of lines in the file) then the calculations do not work and i end up the 'nan' values. Here's my program:

---

#include<iostream>
#include<fstream>
#include<cmath>
using namespace std;


//define my own data structure
struct point {
    double x;
    double y;
    double s;
    double w;
    double wx;
    double wy;
    double wxy;
    double wxx;
    double wmxcy;
};


//main program
int main() {

    //array of point
    point thePoints[11];
    int i = 0;

    //open a file to read in
    ifstream myFile ("xys.data.txt");

    //check if it opened successfully
    if (myFile.is_open() ) {

        //file is open
        //read it in
        while (!myFile.eof() ) {

            //whilst we are not at the end of the file
            myFile >> thePoints[i].x >> thePoints[i].y >> thePoints[i].s;
            //increment i
            i++;
        }

        //close the file
        myFile.close();
    }

    // something went wrong
    else {
        cout << "Error opening file!\n";
        exit(1);
    }

    // data is now in an array of point structures

    //set the summation variables to zero - sets an initial value for the rest of the appropriate array to then be added onto
    double Sw = 0;
    double Swxx = 0;
    double Swxy = 0;
    double Swx = 0;
    double Swy = 0;
    double xsq = 0;


    //create an array for w
    for (int j = 0; j <= 10; j++){
        thePoints[j].w = 1/(pow((thePoints[j].s),2));

    //sum over all w i.e. create an array for Sw
        Sw += thePoints[j].w;

    //create an array for wx
        thePoints[j].wx = (thePoints[j].w) * (thePoints[j].x);

    //sum over all wx i.e. create an array for Swx
        Swx += thePoints[j].wx;

    //create an array for wy
        thePoints[j].wy = (thePoints[j].w) * (thePoints[j].y);

    //sum over all wy i.e. create an array for Swy
        Swy += thePoints[j].wy;

    //create an array for wxy
        thePoints[j].wxy = (thePoints[j].w) * (thePoints[j].x) * (thePoints[j].y);

    //sum over all wxy i.e. create an array for Swxy
        Swxy += thePoints[j].wxy;

    //create an array for wxx
        thePoints[j].wxx = (thePoints[j].w) * (thePoints[j].x) * (thePoints[j].x);

    //sum over all wxx i.e. create an array for Swxx
        Swxx += thePoints[j].wxx;
    }

    printf("%6.2f, %6.2f, %6.2f, %6.2f, %6.2f\n", Sw, Swx, Swy, Swxy, Swxx);

    //caluculate a value for D
    double D = ((Sw * Swxx) - (Swx * Swx));

    //calculate a value for m
    double m = ((Sw * Swxy) - (Swx * Swy))/D;

    //calculate a value for dm
    double dm = sqrt(Sw/D);

    //calculate a value for c
    double c = ((Swy * Swxx) - (Swx * Swxy))/D;

    //calculate a value for dc
    double dc = sqrt(Swxx/D);

    //calculate chi-squared value, xsq = Sw(((m * x) + c - y)^2)
    for (int j = 0; j < i; j++){
        thePoints[j].wmxcy = (thePoints[j].w * (pow(((m * thePoints[j].x) + c - thePoints[j].y),2)));

    //sum over all chi-squared
    xsq += thePoints[j].wmxcy;
    }

    //prints all of the results of the data
        printf("The equation of the line for the data is y = %6.2f x + %6.2f.\n", m, c);
        printf("The gradient, m, has an associated error of %6.2f.\n", dm);
        printf("The y intercept, c, has an associated error of %6.2f.\n", dc);
        printf("The data has a chi-squared value of %6.2f.\n", xsq);

    return 0;
}

I have attached the input file. txt file

Any opinions would be much appreciated.

Answer 1

If you don't know the number of points at compile time then you should use dynamically allocated memory. You can either read the file in two passes to count the number of points, then allocate the memory all at once with new and populate the points during a second pass, or you can use a data structure to store your points that can grow as needed while you read the file. I would suggest you take a look at std::vector from the STL as a starting place. Here's a brief example using std::vector.

//vector of point
std::vector<point> thePoints;

//open a file to read in
ifstream myFile ("xys.data.txt");

//check if it opened successfully
if (myFile.is_open() ) {

    //file is open
    //read it in
    while (!myFile.eof() ) {
        point aPoint;

        //whilst we are not at the end of the file
        myFile >> aPoint.x >> aPoint.y >> aPoint.s;

        //add a point to the vector of points
        thePoints.push_back(aPoint);
    }

    //close the file
    myFile.close();
}

You can get the number of points with thePoints.size() . Make sure you update all your for loops to remove the hardcoded 10.