如何从数组中删除非值

Question

How to clean an array and keep only the numeric values of it. This is my attempt.

var array = ['5441ec', '37df21', '34d72', 'f3117'];

function normalize(input, scale, offset) {
    input = input.map(Number); //remove non-numeric characters.
    var cleanUp = input.filter(val => $.isNumeric(val) ); 
    return cleanUp.map( values => values * scale + offset );
    console.log(cleanUp);
};

normalize(array, 1, 0);

Answer 1

Simply with String.replace() function:

 var arr = ['5441ec', '37df21', '34d72', 'f3117'], res = arr.map((v) => Number(v.replace(/\\D+/g, ''))); console.log(res); 

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• \\D+ - one or more non-digit character(s)

Answer 2

Slightly different to RomanPerekhrest's answer using match rather than replace .

 var array = ['5441ec', '37df21', '34d72', 'f3117']; function normalize(arr) { return arr.map(el => Number(el.match(/\\d+/))); }; console.log(normalize(array)); 

Or, if you want to retain the elements as strings, just leave out the number coercion.

 var array = ['5441ec', '37df21', '34d72', 'f3117']; function normalize(arr) { return arr.map(el => el.match(/\\d+/)[0]); }; console.log(normalize(array));