如何在gnuplot中绘制球体的表面？

Question

How do I plot a white spherical surface? In three dimensions, radius should be 1, center at the origin.

I have scattered point data on the sphere. It is hard to look at it, since the points from the opposite end of the sphere are just as visible. Therefore I would like to create a white spherical "background" on top of which the data is clearly visible.

Restricting the range of one coordinate axis to [0:1] is cumbersome since it cuts off half the points at which I also want to look.

Tanks!

Answer 1

Here is an example, borrowed from the gnuplot demo page . For a white sphere, replace yellow with white :

set parametric
set isosamples 50,50
set hidden

R = 1.   # radius of sphere
set urange [-pi/2:pi/2]
set vrange [0:2*pi]
splot R*cos(u)*cos(v),R*cos(u)*sin(v),R*sin(u) w l lc rgb "yellow", \
"-" w p
1 0 0
-1 0 0
e

You can see that only one of the two data points is visible, while the other is hidden behind the sphere.