去除非ASCII字符的多行字符串

Question

I am trying to get a string into the shell in IDLE. It contains some non-ascii characters that I would like to remove. I can't just paste it into a multi line string, eg

u'''✔uganda
✔zambia
✔zimbabwe
and none of these…
✕afghanistan
✕armenia
✕azerbaijan'''

because that would give me the following error:

Unsupported characters in input

and I can't use

string = [raw_]input()

because the string is more than one line wide.

---

How can I get the string into the shell?

Answer 1

If you cannot define a string like this (on your machine), then you will need to input it. This means that you need some code to accept a multi-line input and as you read each line, check that ord() of each character is less than 256 (ie it is in the ASCII set).

Here is said code:

inpt = ''.join(c for c in input() if ord(c) < 256)
while True:
    s = ''.join(c for c in input() if ord(c) < 256)
    if s:
        inpt += "\n" + s
    else:
        break

and this works:

✔uganda
✔zambia
✔zimbabwe
and none of these…
✕afghanistan
✕armenia
✕azerbaijan

>>> inpt
'uganda\nzambia\nzimbabwe\nand none of these\nafghanistan\narmenia\nazerbaijan'
>>> print(inpt)    
uganda
zambia
zimbabwe
and none of these
afghanistan
armenia
azerbaijan

Answer 2

If you have data stored in your session and can't just execute a script, then you could just run an input loop to copy in the full input.

code:

inp = ""


for line in iter(input, “”):
        inp += line

Answer 3

Define it in a script. File, New, then:

#!coding:utf8
s = u'''✔uganda
✔zambia
✔zimbabwe
and none of these…
✕afghanistan
✕armenia
✕azerbaijan'''
print s

Save it, then press F5 to run it in the IDLE shell. Output:

✔uganda
✔zambia
✔zimbabwe
and none of these…
✕afghanistan
✕armenia
✕azerbaijan

Alternatively, swith to the latest Python. 3.6's Idle works fine:

>>> s='''\
✔uganda
✔zambia
✔zimbabwe
and none of these…
✕afghanistan
✕armenia
✕azerbaijan'''
>>> print(s)
✔uganda
✔zambia
✔zimbabwe
and none of these…
✕afghanistan
✕armenia
✕azerbaijan