[英]Remove object from nested array if array is empty in Typescript
How can I remove the object if the nested array is empty. 如果嵌套数组为空,如何删除对象。 Like I have an array: 就像我有一个数组:
pokemonGroups = [
{
name: 'Grass',
pokemon: [
'bulbasaur-0', 'Bulbasaur', 'oddish-1','Oddish','bellsprout-2', 'Bellsprout'
]
},
{
name: 'Water',
pokemon: [
]
}]
So In this we have an empty array 所以在这个我们有一个空数组
{
name: 'Water',
pokemon: []
}
So I want to remove this object and my array should be like: 所以我想删除这个对象,我的数组应该像这样:
pokemonGroups = [
{
name: 'Grass',
pokemon: [
'bulbasaur-0', 'Bulbasaur', 'oddish-1','Oddish','bellsprout-2', 'Bellsprout'
]
}
]
您可以使用过滤器:
pokemonGroups = pokemonGroups.filter(group => group.pokemon.length != 0);
You can iterate your array and use array.splice() 您可以迭代数组并使用array.splice()
var pokemonGroups = [{ name: 'Grass', pokemon: [ 'bulbasaur-0', 'Bulbasaur', 'oddish-1', 'Oddish', 'bellsprout-2', 'Bellsprout' ] }, { name: 'Water', pokemon: [ ] } ] for (var i = 0; i < pokemonGroups.length; i++) { if (pokemonGroups[i]['pokemon'].length == 0) { pokemonGroups.splice(i, 1); } } console.log(pokemonGroups)
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