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如何比较两个数组对象-Swift 4

[英]How do I compare two array Objects - Swift 4

I have 2 Array of type [Any] - objects of dictionaries 我有2个[Any]类型的数组-字典对象
And other array contains other set of objects [Any] (2nd array objects are contains in first array) 其他数组包含其他对象集[Any] (第二个数组对象包含在第一个数组中)

I need to find the index of the first array of second array elements 我需要找到第二个数组元素的第一个数组的索引

eg: - 例如:-

let firstArray = [["key1":6],["key2":8],["key3":64],["key4":68],["key5":26],["key6":76]]

let secondArray = [["key3":64],["key6":68]]

How can I find the firstArray index of secondArray elements 我如何找到secondArray元素的firstArray索引

let index = firstArray.index{$0 == secondArray[0]};
print("this value ", index);

will print optional(2) , it is basically 2 将打印optional(2),基本上是2

First, you take the keys from your secondArray . 首先,从secondArray获取密钥 Then, you try to find the index of key in your firstArray . 然后,您尝试在firstArray找到键的索引 Be aware that some values might be nil if the key doesn't exist. 请注意,如果键不存在,则某些值可能为nil。

let firstArray = [["key1":6],["key2":8],["key3":64],["key4":68],["key5":26],["key6":76]]
let secondArray = [["key3":64],["key6":68], ["key8": 100]]

let indexes = secondArray
    .map({ $0.first?.key }) //map the values to the keys
    .map({ secondKey -> Int? in
        return firstArray.index(where:
            { $0.first?.key == secondKey } //compare the key from your secondArray to the ones in firstArray
        )
    })

print(indexes) //[Optional(2), Optional(5), nil]

I also added an example case where the result is nil. 我还添加了一个示例案例,结果为零。

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