将字符串重新排列为二维数组python

Question

I have the following string after using urllib:

459,2277,617459268\n14619,99,19600737\n11297,99,18666551\n16603,99,19761406\n12660,99,28741324\n4543

after using replace and split:

data = data.replace('\\n', ',').split(',')

['459', '2277', '617459268', '14619', '99', '19600737', '11297', '99', '18666551', '16603', '99', '19761406', '12660', '99', '28741324', '4543']

However, I had like to get the following 2D array:

459 2277 617459268
14619 99 19600737
11297 99 18666551...

Is there a way to break this 1D array into a 2D array without using numpy ?

When I say 2D array I mean column list when each row is 1x3 list.

Easy ways will be appreciated.

Thank you.

Answer 1

Don't replace your "row delimiters" by "column delimiters". Instead, for split the string on the row delimiter. Then split each row on the column delimiter.

If your input has new line characters:

rows = data.split()

If your input has a literal backslash followed by the letter n rather than a newline character:

rows = data.split('\\n')

Either way, now you can split each row on commas:

matrix = [row.split(',') for row in rows]

Answer 2

save this str to string like s then :

s='''459,2277,617459268\n14619,99,19600737\n11297,99,18666551\n16603,99,19761406\n12660,99,28741324\n4543'''

for i in s.split('\n'):
    print (i)


459,2277,617459268
14619,99,19600737
11297,99,18666551
16603,99,19761406
12660,99,28741324
4543

or if you want to print without , :

for i in s.replace(',' , ' ').split('\n'):
    print (i)


459 2277 617459268
14619 99 19600737
11297 99 18666551
16603 99 19761406
12660 99 28741324
4543