[英]Bash How to execute a command for files in two directories
I know this bash code for execute an operation for all files in one directory: 我知道此bash代码可对一个目录中的所有文件执行操作:
for files in dir/*.ext; do
cmd option "${files%.*}.ext" out "${files%.*}.newext"; done
But now I have to execute an operation for all files in one directory with all files in another directory with the same filename but different extension. 但是,现在我必须对一个目录中的所有文件以及另一个目录中的所有文件具有相同文件名但具有不同扩展名的所有文件执行操作。 For example
例如
directory 1 -> file1.txt, file2.txt, file3.txt
directory 2 -> file1.csv, file2.csv, file3.csv
cmd file1.txt file1.csv > file1.newext
cmd file2.txt file2.csv > file2.newext
I must not to compare two files, but the script that I have to execute needs two file to produce another one (in particular I have to execute bwa samsa path_to_ref/ref file1.txt file1.csv > file1.newext
) 我不能比较两个文件,但是我必须执行的脚本需要两个文件才能生成另一个文件(尤其是我必须执行
bwa samsa path_to_ref/ref file1.txt file1.csv > file1.newext
)
Could you help me? 你可以帮帮我吗?
Thank you for your answers! 谢谢您的回答!
In bash using variable manipulation: 在bash中使用变量操作:
$ for f in test/* ; do t="${f##*/}"; echo "$f" test2/"${t%.txt}".csv ; done
test/file1.txt test2/file1.csv
test/file2.txt test2/file2.csv
test/file3.txt test2/file3.csv
Edit: 编辑:
Implementing @DavidC.Rankin's insuring suggestion: 实施@ DavidC.Rankin的保险建议:
$ touch test/futile
for f in test/*
do
t="${f##*/}"
t="test2/${t%.txt}".csv
if [ -e "$t" ]
then
echo "$f" "$t"
fi
done
test/file1.txt test2/file1.csv
test/file2.txt test2/file2.csv
test/file3.txt test2/file3.csv
Try with: 尝试:
for file in path_to_txt/*.txt; do
b=$(basename $file .txt)
cmd path_to_txt/$b.txt path_to_csv/$b.csv
done
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