如何退回虚假承诺？

Question

I have this code:

  var updateLogin = function updateLogin() {
     var parameters = $location.search();
     if(parameters.votoken) {
         // return a promise
         return authenticationService.updateCurrentToken(parameters);
     }

    //just logout and redirect to match another route
    authenticationService.logout()['finally'](function logoutComplete() {
        $location.url('/unauthorized');
    });
  }

    var redirectToHome = function redirectToHome() {

    $injector.invoke(updateLogin).then(() => {
           //some action here
    });
  }  


  redirectToHome();

As you can see, if the updateLogin method matches a condition it will return a promise and it works fine, but if not, the method doesnt return a promise and redirect the user to a new location, then i get this error on console Cannot read property 'then' of undefined and its obvious why. I would like to know what is the best approach to avoid that. If I return the authenticationService.logout() promise, how do I know if i will need to execute this method $location.url('/unauthorized'); on the .then(() => snippet?

Answer 1

Can return $q.reject() in your else . Remember to also inject $q