根据数字和组ID扩展熊猫数据框行（Python 3）。

Question

I have been struggling with finding a way to expand/clone observation rows based on a pre-determined number and a grouping variable (id). For context, here is an example data frame using pandas and numpy (python3).

df = pd.DataFrame([[1, 15], [2, 20]], columns = ['id', 'num'])

df
Out[54]:
  id  num
0   1   15
1   2   20 

I want to expand/clone the rows by the number given in the "num" variable based on their ID group. In this case, I would want 15 rows for id = 1 and 20 rows for id = 2. This is probably an easy question, but I am struggling to make this work. I've been messing around with reindex and np.repeat, but the conceptual pieces are not fitting together for me.

In R, I used the expandRows function found in the splitstackshape package, which would look something like this:

library(splitstackshape)

df <- data.frame(id = c(1, 2), num = c(15, 20))


df
  id num
1  1  15
2  2  20


df2 <- expandRows(df, "num", drop = FALSE)
df2
     id num
1     1  15
1.1   1  15
1.2   1  15
1.3   1  15
1.4   1  15
1.5   1  15
1.6   1  15
1.7   1  15
1.8   1  15
1.9   1  15
1.10  1  15
1.11  1  15
1.12  1  15
1.13  1  15
1.14  1  15
2     2  20
2.1   2  20
2.2   2  20
2.3   2  20
2.4   2  20
2.5   2  20
2.6   2  20
2.7   2  20
2.8   2  20
2.9   2  20
2.10  2  20
2.11  2  20
2.12  2  20
2.13  2  20
2.14  2  20
2.15  2  20
2.16  2  20
2.17  2  20
2.18  2  20
2.19  2  20

Again, sorry if this is a stupid question and thanks in advance for any help.

Answer 1

I can't replicate your index, but I can replicate your values, using np.repeat , quite easily in fact.

v = df.values
df = pd.DataFrame(v.repeat(v[:, -1], axis=0), columns=df.columns)

---

If you want the exact index (although I can't see why you'd need to), you'd need a groupby operation -

def f(x):
    return x.astype(str) + '.' + np.arange(len(x)).astype(str)

idx = df.groupby('id').id.apply(f).values

Assign idx to df 's index -

df.index = idx