bash将git命令结果添加到局部变量

Question

I am trying to change the name of my file, adding the number of commits and the current branch name on my file before sending it to the repository.

But I get the following error:

./publish_to_artifactory.sh: line 4: local: `rev-parse': not a valid identifier'`

upload() {
  local currentBranch=git rev-parse --abbrev-ref HEAD;
  local gitNumberOfCommits=git rev-list --count HEAD;

  for file in ./../*.ipa; do
    mv $file mobile-${currentBranch}-${gitNumberOfCommits};
    echo "uploading zeos-mobile-$currentBranch-$gitNumberOfCommits";
    curl -X PUT -u $PUBLISH_USER:$PUBLISH_PASS -T mobile-$currentBranch-$gitNumberOfCommits; http://example.com/artifactory/ios-dev-local/ --fail
  done
}

upload;

What am I doing wrong?

Answer 1

To assign the output of a command to a variable, you need to use command-substitution syntax in bash .

local currentBranch="$(git rev-parse --abbrev-ref HEAD)"
local gitNumberOfCommits="$(git rev-list --count HEAD)"

What you have done is stored the literal string in those local variables defined. When shell was tokenizing them to evaluate it has understood it as a variable assignment gone horribly wrong! What it understood is a local variable in the name of currentBranch set to a value git and tries to run rev-list as a command which it cannot obviously find in its list of standard paths (under $PATH )