[英]Conditional link arm64/armv7
I have a .a
library that was compiled only for the arm64
architecture and I don't have access to the source code. 我有一个
.a
库,仅针对arm64
体系结构进行了编译,但无法访问源代码。
I added preprocessor flags to disable the usage of the library when compiling under armv7
我添加了预处理器标志以在
armv7
下编译时禁用库的使用
#if arch(arm64)
// Instatiate an object of the library and use it
#else
// Do nothing (for armv7)
#endif
The linking is done via Other linker flags
but I am getting the error "Invalid bitcode signature" / Linker command failed. 链接是通过
Other linker flags
完成的,但出现错误“无效的位码签名” /链接器命令失败。
Is there a way to conditionally link the library? 有条件地链接库的方法吗? I am using Xcode 9
我正在使用Xcode 9
What I actually end up doing to silence the compiler is create a FAT library with no compiled code for the other architectures. 我实际上最终要使编译器保持沉默的方法是创建一个FAT库,而没有其他体系结构的已编译代码。 This would solve the problem as the library is not needed during the linking process
这将解决问题,因为在链接过程中不需要该库
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