从命令行递归多行查找/替换

Question

I am trying to do a find and replace for import statements in js files. There are a few different variants that I need to be able to account for:

// default-import.js
import foo from 'bar-shared';

// named-import.js
import {Foo} from 'bar-shared/foo';

// type-import.js
import type {FooType} from 'bar-shared/foo';

// multiline-import.js
import {
  Foo,
  reduceFoo,
} from 'bar-shared/foo';

// multiline-with-type-import.js
import {
  Foo,
  reduceFoo,
  type FooType,
} from 'bar-shared/foo';

// multiple-import.js
import foo from 'bar-shared';
import {Foo} from 'bar-shared/foo';
import {
  Baz
  reduceBaz
} from 'bar-shared/baz';

My end goal is to replace bar-shared with @bar/core . But the limitations are: - I don't know what the specific imports are - An import statement can be over multiple lines - There can be multiple import statements for bar-shared in a single file

I have gotten reasonably close on with the following:

find . -type f -name "*.js" -exec \
  perl -0777 -p -i -e "s/^import ([\s\S]*?) from 'bar-shared(.*)'/import \1 from '\@bar\/core\2'/gms" {} +

That script doesn't seem to be finding all of the instances though. Specifically the final example type, with more than one import statement in the file, seems to be the real problem.

Answer 1

It seems that you always need to match from import to the first from 'bar-shared' . Then

perl -i -0777 -wpe's{import.*?from\s+\x27\Kbar\-shared}{\@bar/core}gs'

The \\x27 is the hexadecimal escape for the single quote (27). The /s modifier makes . match newlines, too, which is all you need to process this multiline string in this way. The \\K discards all previous matches so they need not be captured and replaced.

Tested on your example but I am not sure what may appear inside import blocks in JS.