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SQL:使用一列中的不同值来选择另一列中的所有对应的不同值

[英]SQL: use distinct values in one column to select all corresponding distinct values in another column

Suppose I have a data set such as this: 假设我有一个像这样的数据集:

ColA    ColB
====    ====
Foo     Green
Foo     Purple
Bar     Magenta
Bar     Green
Foo     Purple
Bar     Purple
Bar     Purple
Foo     Green
Bar     Green

I would like to query this data and return the below. 我想查询此数据并返回以下内容。 Essentially, take all distinct values from ColA (Foo & Bar) and return all distinct values for EACH of them from ColB: 本质上,从ColA(Foo和Bar)中获取所有不同的值,并从ColB中返回每个EACH的所有不同值:

ColA    ColB
====    ====
Foo     Green
Foo     Purple
Bar     Magenta
Bar     Green
Bar     Purple

I know I'm overthinking this...but I can't seem to hammer it out... 我知道我想得太多了...但是我似乎无法解决...

Please use of of the below - 请使用以下-

SELECT DISTINCT cola,colb FROM yourtableName

OR 要么

SELECT cola,colb From yourtableName
GROUP BY cola,colb

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