Openpyxl Python-如何遍历大文件并在特定列中返回值

Question

I am quite new to programming and am using openpyxl to return some values from a spreadsheet.

The spreadsheet is large and contains about 90,000 rows and 50 columns.

I've created a simplified version of the problem in the image below with just a few rows:
Excel Screenshot Here
What I am trying to do is iterate through all the rows in the spreadsheet and where column B = "Y", take the corresponding value of the cell in the column "code" and perform a function with that code.

I've been trying to use sheet.iter_rows but not had much luck and have had some really slow performance.

for y_row in sheet.iter_rows(min_row=1, max_row=4, min_col=2, max_col=4):
        for cell in row:
            if cell.value == "Y"

How do I get cell.value to refer specifically to column 2?

Any help would be much appreciated.

Answer 1

If you don't need to edit the file then you can take advantage of read-only mode. This will load the file much faster.

wb = load_workbook(filename_and_path, read_only=True)
ws = wb.active
# Only look at cells in column B
for row in ws.iter_rows(min_col=2, max_col=2):
    if row[0].value:
        # code body.

Answer 2

Try:

ckecked = 2
code = 4

for y_row in sheet.iter_rows(min_row=1, max_row=4, min_col=2, max_col=4):
    if y_row[checked-1].value == "Y":
        myfunc( y_row[code-1].value )